NEET (Medical) · Physics
Ray Optics and Optical Instruments
15 practice questions with full step-by-step solutions — free, no sign-up.
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Ray Optics and Optical Instruments — solved practice questions
8 NEET Physics questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1easy
The power of a thin lens of focal length 25 cm is:
- A2.5 D
- B4 D
- C5 D
- D0.25 D
Show answer & solution
Correct answer: (B) 4 D
Power P = 1/f (in metres) = 100/25 cm = 4 dioptres.
- Q2medium
An object is placed 30 cm in front of a convex lens of focal length 20 cm. The image is formed at a distance of:
- A12 cm
- B20 cm
- C30 cm
- D60 cm
Show answer & solution
Correct answer: (D) 60 cm
Using 1/v − 1/u = 1/f with u = −30, f = +20: 1/v = 1/20 − 1/30 = 1/60, so v = 60 cm (real, on the other side).
- Q3medium
An object is placed 30 cm from a concave mirror of focal length 15 cm. The magnification of the image is:
- A−1
- B−2
- C+1
- D+2
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Correct answer: (A) −1
1/v + 1/u = 1/f with u = −30, f = −15 gives v = −30 cm. Magnification m = −v/u = −(−30)/(−30) = −1 (real, inverted, same size).
- Q4medium
The critical angle for a medium of refractive index 1.5 (with respect to air) is closest to:
- A30°
- B36°
- C42°
- D48°
Show answer & solution
Correct answer: (C) 42°
sin C = 1/n = 1/1.5 = 0.667, so C ≈ 42°.
- Q5medium
A ray travels from a denser medium of refractive index √2 into air. The critical angle for total internal reflection is:
- A30°
- B45°
- C60°
- D90°
Show answer & solution
Correct answer: (B) 45°
sin C = 1/n = 1/√2, so C = 45°.
- Q6easy
The speed of light in a medium of refractive index 1.5 is (c = 3 × 10^8 m/s):
- A3 × 10^8 m/s
- B4.5 × 10^8 m/s
- C1.5 × 10^8 m/s
- D2 × 10^8 m/s
Show answer & solution
Correct answer: (D) 2 × 10^8 m/s
v = c/n = 3 × 10^8 / 1.5 = 2 × 10^8 m/s.
- Q7medium
Two thin lenses of powers +5 D and −2.5 D are placed in contact. The power of the combination is:
- A+2.5 D
- B+7.5 D
- C−2.5 D
- D+1.25 D
Show answer & solution
Correct answer: (A) +2.5 D
For lenses in contact powers add: P = P1 + P2 = +5 + (−2.5) = +2.5 D.
- Q8hard
An equiconvex lens is made of glass of refractive index 1.5, each surface having radius of curvature 20 cm. Its focal length is:
- A10 cm
- B15 cm
- C20 cm
- D40 cm
Show answer & solution
Correct answer: (C) 20 cm
Lensmaker: 1/f = (n−1)(1/R1 − 1/R2) = (0.5)(1/20 − 1/(−20)) = (0.5)(2/20) = 1/20, so f = 20 cm.
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