Problems on Ages

What you'll learn

Learn the one-variable method for age problems: handling past and future ages, the constant-difference rule, and ratio-based questions for SSC-CGL.

This chapter has

Problems on Ages — solved practice questions

8 SSC / Banking Quantitative Aptitude questions with step-by-step solutions. Attempt each, then reveal the answer.

1. Q1easy

   A is 5 years older than B. If B is 20, what is A's age?

   • A20
   • B25
   • C15
   • D30
   Show answer & solution

   Correct answer: (B) 25

   A = B + 5 = 25.

2. Q2easy

   The ratio of ages of A and B is 3:4. If A is 18, B's age is:

   • A12
   • B21
   • C24
   • D27
   Show answer & solution

   Correct answer: (C) 24

   3/4 = 18/B → B = 24.

3. Q3medium

   10 years ago, Ravi was twice as old as Mohan. If their sum now is 55, Ravi's present age is:

   • A25
   • B28
   • C30
   • D32
   Show answer & solution

   Correct answer: (C) 30

   Let Mohan = m now. 10 yrs ago: R−10 = 2(m−10) and R+m = 55. Solving: R = 30, m = 25.

4. Q4hard

   The sum of ages of father and son is 45. Five years ago the product of their ages was 4 times the father's age at that time. Father's present age:

   • A30
   • B34
   • C36
   • D40
   Show answer & solution

   Correct answer: (C) 36

   Let father = f, son = s = 45−f. 5 yrs ago: (f−5)(s−5) = 4(f−5) → s−5 = 4 → s = 9, f = 36.

5. Q5hard

   A is twice as old as B was when A was as old as B is now. If A is 28, B is:

   • A14
   • B18
   • C21
   • D24
   Show answer & solution

   Correct answer: (C) 21

   Let B = b now. Difference = A−B = 28−b. B was (b−(28−b)) when A was b. So 28 = 2(b−28+b) → 28 = 4b−56 → b = 21.

6. Q6easy

   Rani is 3 years younger than Geeta and 3 years older than Priya. If Geeta is 18, Priya's age is:

   • A9
   • B12
   • C15
   • D18
   Show answer & solution

   Correct answer: (B) 12

   Rani = 18−3 = 15. Priya = 15−3 = 12.

7. Q7medium

   The present age of a father is 3 times his son's age. After 10 years it will be twice. Son's present age:

   • A5
   • B8
   • C10
   • D12
   Show answer & solution

   Correct answer: (C) 10

   f = 3s. After 10: f+10 = 2(s+10) → 3s+10 = 2s+20 → s = 10.

8. Q8medium

   A man is 24 years older than his son. In 2 years his age will be twice his son's. Son's present age:

   • A18
   • B20
   • C22
   • D24
   Show answer & solution

   Correct answer: (C) 22

   f = s+24. f+2 = 2(s+2) → s+26 = 2s+4 → s = 22.

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