Structure of Atom

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Structure of Atom — solved practice questions

8 NEET Chemistry questions with step-by-step solutions. Attempt each, then reveal the answer.

1. Q1easy

   The maximum number of electrons that can be accommodated in the shell with principal quantum number n = 3 is:

   • A8
   • B9
   • C18
   • D32
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   Correct answer: (C) 18

   Maximum electrons in a shell = 2n^2 = 2 x 3^2 = 18.

2. Q2easy

   The number of orbitals present in the n = 3 shell is:

   • A3
   • B9
   • C6
   • D18
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   Correct answer: (B) 9

   Number of orbitals in a shell = n^2 = 3^2 = 9 (one 3s, three 3p, five 3d).

3. Q3easy

   The azimuthal quantum number (l) for a 3d orbital is:

   • A3
   • B0
   • C1
   • D2
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   Correct answer: (D) 2

   For d subshells, l = 2 (s = 0, p = 1, d = 2, f = 3).

4. Q4medium

   According to Bohr's model, the energy of an electron in the second orbit (n = 2) of a hydrogen atom is: (E = -13.6/n^2 eV)

   • A-3.4 eV
   • B-13.6 eV
   • C-1.51 eV
   • D-6.8 eV
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   Correct answer: (A) -3.4 eV

   E = -13.6 / n^2 = -13.6 / 4 = -3.4 eV.

5. Q5hard

   The de Broglie wavelength of an electron (mass 9.1 x 10^-31 kg) moving with a velocity of 1.0 x 10^6 m/s is approximately: (h = 6.626 x 10^-34 J s)

   • A7.28 x 10^-7 m
   • B7.28 x 10^-12 m
   • C7.28 x 10^-10 m
   • D3.64 x 10^-10 m
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   Correct answer: (C) 7.28 x 10^-10 m

   Lambda = h / (m v) = 6.626 x 10^-34 / (9.1 x 10^-31 x 1.0 x 10^6) = 7.28 x 10^-10 m.

6. Q6medium

   The number of radial nodes in a 4s orbital is:

   • A0
   • B3
   • C4
   • D1
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   Correct answer: (B) 3

   Number of radial nodes = n - l - 1 = 4 - 0 - 1 = 3.

7. Q7hard

   Which set of quantum numbers is NOT permitted for an electron in an atom?

   • An = 3, l = 2, m = -1
   • Bn = 4, l = 0, m = 0
   • Cn = 2, l = 1, m = +1
   • Dn = 2, l = 2, m = 0
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   Correct answer: (D) n = 2, l = 2, m = 0

   For a given n, l ranges from 0 to n-1. The set n = 2, l = 2 is not allowed because when n = 2 the maximum value of l is 1.

8. Q8medium

   The ionization energy of the He+ ion (a hydrogen-like species, Z = 2) is: (for hydrogen-like species IE = 13.6 x Z^2 eV)

   • A54.4 eV
   • B13.6 eV
   • C27.2 eV
   • D6.8 eV
   Show answer & solution

   Correct answer: (A) 54.4 eV

   IE = 13.6 x Z^2 = 13.6 x 4 = 54.4 eV.

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