Class 12 (CBSE) · Physics
Current Electricity
15 practice questions with full step-by-step solutions, plus a concept-first explainer — free, no sign-up.
What you'll learn
A friendly, first-principles walk through Current Electricity for CBSE Class 12 — electric current, Ohm's law, resistivity, series and parallel resistors, Kirchhoff's rules and the Wheatstone bridge — with everyday analogies, correct SI units, and a fully worked numerical.
Read Current Electricity Made Simple: From Ohm's Law to the Wheatstone BridgeThis chapter has
Current Electricity — solved practice questions
8 Class 12 Physics questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1easy
The resistance of a conductor is 10 ohm and the potential difference across it is 5 V. The current through it is
- A2 A
- B0.5 A
- C50 A
- D5 A
Show answer & solution
Correct answer: (B) 0.5 A
By Ohm's law I = V/R = 5/10 = 0.5 A.
- Q2easy
The drift velocity of free electrons in a conductor is directly proportional to
- Athe square of the applied electric field
- Bthe cross-sectional area of the conductor
- Cthe number density of electrons
- Dthe applied electric field
Show answer & solution
Correct answer: (D) the applied electric field
Drift velocity v_d = eE tau/m, so v_d is directly proportional to the applied electric field E.
- Q3easy
The SI unit of electrical resistivity is
- Aohm metre (ohm m)
- Bohm per metre (ohm m^-1)
- Cohm (ohm)
- Dsiemens (S)
Show answer & solution
Correct answer: (A) ohm metre (ohm m)
From rho = R A / L, resistivity has units of ohm x metre (ohm m).
- Q4easy
Three resistors of 2 ohm, 3 ohm and 5 ohm are connected in series. Their equivalent resistance is
- A0.97 ohm
- B3.33 ohm
- C10 ohm
- D30 ohm
Show answer & solution
Correct answer: (C) 10 ohm
In series resistances add: R = 2 + 3 + 5 = 10 ohm.
- Q5medium
Two resistors of 6 ohm and 3 ohm are connected in parallel. The equivalent resistance is
- A9 ohm
- B2 ohm
- C4.5 ohm
- D18 ohm
Show answer & solution
Correct answer: (B) 2 ohm
For parallel, R = (R1 R2)/(R1 + R2) = (6 x 3)/(6 + 3) = 18/9 = 2 ohm.
- Q6medium
A cell of emf 2 V and internal resistance 0.5 ohm is connected to an external resistance of 1.5 ohm. The current in the circuit is
- A0.5 A
- B1.33 A
- C4 A
- D1 A
Show answer & solution
Correct answer: (D) 1 A
I = E/(R + r) = 2/(1.5 + 0.5) = 2/2 = 1 A.
- Q7medium
An electric bulb is rated 60 W at 220 V. The resistance of its filament is approximately
- A807 ohm
- B3.67 ohm
- C220 ohm
- D13200 ohm
Show answer & solution
Correct answer: (A) 807 ohm
R = V^2/P = (220)^2/60 = 48400/60 = 807 ohm approximately.
- Q8medium
Kirchhoff's junction rule (current rule) is based on the conservation of
- Aenergy
- Bmomentum
- Ccharge
- Dmass
Show answer & solution
Correct answer: (C) charge
The junction rule states that total current entering a junction equals total current leaving it, which is a statement of conservation of charge.
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