Class 12 (CBSE) · Biology
Molecular Basis of Inheritance
15 practice questions with full step-by-step solutions, plus a concept-first explainer — free, no sign-up.
What you'll learn
A from-scratch guide to DNA's double-helix structure, the classic experiments proving DNA is the genetic material, semiconservative replication, and the central dogma of transcription, the genetic code, and translation — built for CBSE Class 12 boards, NEET and CUET.
Read Molecular Basis of Inheritance: DNA, Its Proof, and How the Cell Reads ItThis chapter has
Molecular Basis of Inheritance — solved practice questions
8 Class 12 Biology questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1easy
In a DNA double helix, adenine pairs with thymine through how many hydrogen bonds?
- AOne
- BTwo
- CThree
- DFour
Show answer & solution
Correct answer: (B) Two
Adenine (A) and thymine (T) form a complementary base pair held by two hydrogen bonds.
- Q2easy
The number of hydrogen bonds formed between guanine and cytosine in DNA is:
- ATwo
- BOne
- CThree
- DFour
Show answer & solution
Correct answer: (C) Three
Guanine (G) pairs with cytosine (C) through three hydrogen bonds, making G-C pairs more stable than A-T pairs.
- Q3medium
According to Chargaff's rule, in a double-stranded DNA molecule:
- AA = C and G = T
- BA + T = G + C
- CA = G and T = C
- DA = T and G = C
Show answer & solution
Correct answer: (D) A = T and G = C
Because of complementary base pairing, the amount of adenine equals thymine and guanine equals cytosine, i.e. A = T and G = C.
- Q4easy
The semiconservative mode of DNA replication was experimentally proved in Escherichia coli by:
- AMeselson and Stahl
- BGriffith
- CHershey and Chase
- DWatson and Crick
Show answer & solution
Correct answer: (A) Meselson and Stahl
Meselson and Stahl (1958) used density-gradient centrifugation with 15N/14N labelling of E. coli DNA to demonstrate semiconservative replication.
- Q5medium
In the Watson–Crick model of B-DNA, the distance between two consecutive base pairs along the axis is about:
- A0.34 nm
- B3.4 nm
- C34 nm
- D0.034 nm
Show answer & solution
Correct answer: (A) 0.34 nm
The rise per base pair is 0.34 nm; one full turn of the helix is 3.4 nm and contains about 10 base pairs (3.4 nm / 0.34 nm).
- Q6medium
The enzyme that catalyzes the polymerization of deoxyribonucleotides during DNA replication is:
- ARNA polymerase
- BDNA polymerase
- CDNA ligase
- DHelicase
Show answer & solution
Correct answer: (B) DNA polymerase
DNA-dependent DNA polymerase adds deoxyribonucleotides using the template strand; ligase joins fragments and helicase unwinds the helix.
- Q7hard
During DNA replication, the strand synthesized discontinuously as short Okazaki fragments is the:
- ALeading strand
- BTemplate strand
- CLagging strand
- DCoding strand
Show answer & solution
Correct answer: (C) Lagging strand
Because DNA polymerase works only 5'→3', the lagging strand (with template of 5'→3' polarity in the direction of the fork) is made discontinuously as Okazaki fragments later joined by ligase.
- Q8medium
In eukaryotes the primary transcript (hnRNA) contains exons and introns; the removal of introns and joining of exons is called:
- ACapping
- BTailing
- CTranscription
- DSplicing
Show answer & solution
Correct answer: (D) Splicing
Splicing removes the non-coding introns and joins the coding exons to form mature mRNA. Capping and tailing are other processing steps.
Want the full set? Practise all 15 Molecular Basis of Inheritance questions →