Number System — The Foundation of All Quant

A concept-first guide to the Number System for SSC-CGL: how numbers are classified, must-know divisibility rules, key sum formulas, the unit-digit (cyclicity) trick with a worked example, and a quiz to test yourself.

By the PadhoDost Team · 📖 7 min read · Updated 4 August 2026

Part of SSC CGL & Banking prep

🧠 A family tree of numbers

Think of numbers like a family. The counting numbers 1, 2, 3... are the youngest children (natural numbers). Add zero and they become whole numbers. Bring in the negatives and you have integers. Add all the fractions and you get rational numbers, and finally the odd cousins like the square root of 2 and pi that never settle into a neat fraction — the irrationals. Together the whole family makes up the real numbers.

The Number System is the base of every Quant topic, so knowing exactly which family a number belongs to, and a few quick rules, lets you solve questions in seconds instead of doing long calculations.

TypeMeaningExamples
Natural (N)Counting numbers from 11, 2, 3, 4, ...
Whole (W)Naturals together with 00, 1, 2, 3, ...
Integers (Z)Positives, negatives and zero..., -2, -1, 0, 1, 2, ...
Rational (Q)Can be written as p/q, q not 01/2, -3, 0.75, 4
IrrationalNon-terminating, non-repeating decimalssqrt(2), pi, sqrt(3)
PrimeExactly two factors: 1 and itself2, 3, 5, 7, 11 (2 is the only even prime)

Divisibility Rules You Must Know

Divisible byQuick test
2Last digit is even (0,2,4,6,8)
3Sum of all digits is divisible by 3
4Number formed by the last two digits is divisible by 4
5Last digit is 0 or 5
6Divisible by both 2 and 3
8Number formed by the last three digits is divisible by 8
9Sum of all digits is divisible by 9
10Ends in 0
11Difference between the sums of alternate digits is 0 or a multiple of 11

Key Sum Formulas

1 + 2 + 3 + ... + n = n(n+1)/2
1^2 + 2^2 + ... + n^2 = n(n+1)(2n+1)/6
1^3 + 2^3 + ... + n^3 = [ n(n+1)/2 ]^2
Sum of first n odd numbers = n^2 ; Sum of first n even numbers = n(n+1)

Finding the Unit (Last) Digit

The last digit of a power repeats in a short cycle called its cyclicity. For most digits the cycle length is 4, so you just divide the power by 4 and use the remainder to pick the answer. Digits 0, 1, 5 and 6 always keep the same last digit, so they need no cycle.

📝 Worked example — unit digit of 3^47

Powers of 3 end in a repeating cycle: 3, 9, 7, 1 (then it repeats every 4).

Divide the power by 4: 47 divided by 4 = 11 remainder 3.

A remainder of 3 points to the 3rd number in the cycle 3, 9, 7, 1.

The 3rd term is 7.

Answer: the unit digit of 3^47 is 7.

💡 Cyclicity shortcut: when the power is an exact multiple of 4 (remainder 0), take the LAST digit of the cycle. For 3, that last digit is 1, so 3^48, 3^100, and so on all end in 1.
⚠️ Do not confuse factors with multiples. Factors of a number divide it exactly (factors of 12 are 1, 2, 3, 4, 6, 12), while multiples are the times-table of that number (12, 24, 36, ...). And remember 1 is neither prime nor composite.

Remember these

  • Know the number families: natural, whole, integer, rational, irrational, real.
  • 2 is the only even prime number; 1 is neither prime nor composite.
  • Master the divisibility rules for 2, 3, 4, 5, 6, 8, 9, 10 and 11.
  • Sum of first n natural numbers = n(n+1)/2, and sum of first n odd numbers = n^2.
  • Use cyclicity (usually a cycle of 4) to find the last digit of large powers.

⚡ Quick check

Which of these numbers is divisible by 9?

Ready to test yourself? 🎯

Lock it in with the practice test for this chapter.

Take the practice test →

Keep studying

See all SSC CGL & Banking study material →