Triangles: The Magic of Similarity

Master similar triangles, the Basic Proportionality Theorem, and the criteria (AA, SSS, SAS) that power Class 10 geometry proofs and problems.

By the PadhoDost Team ยท ๐Ÿ“– 7 min read ยท Updated 4 August 2026

Part of Class 10 (CBSE) prep

๐Ÿง  The photocopy machine

Imagine you put a triangular sticker on a photocopier and press 'enlarge to 150%'. The copy is bigger, but it is the exact same shape - every angle is unchanged and every side has grown by the same factor. That is the whole idea of similar triangles: same shape, different size. Two triangles are similar when one is just a scaled-up or scaled-down photocopy of the other.

In this chapter we move from 'congruent' triangles (same shape AND same size) to 'similar' triangles (same shape, possibly different size). Similarity unlocks a huge range of real problems - finding the height of a tree from its shadow, the width of a river you cannot cross, or a distance on a map.

When are two triangles similar?

A B C โˆ A + โˆ B + โˆ C = 180ยฐ
The three interior angles of any triangle always add up to 180ยฐ.

Two triangles are similar if their corresponding angles are equal AND their corresponding sides are in the same ratio (proportion). If triangle ABC is similar to triangle PQR, we write it as triangle ABC ~ triangle PQR, and the order of letters tells you which vertices match.

If ABC ~ PQR then: angle A = angle P, angle B = angle Q, angle C = angle R, and AB/PQ = BC/QR = CA/RP.
๐Ÿ’ก Always write similar triangles in matching order. In ABC ~ PQR, A pairs with P, B with Q, C with R. Writing the order correctly makes the side ratios line up automatically and saves you from silly mistakes.

The Basic Proportionality Theorem (Thales' Theorem)

This is the star result of the chapter. If a line is drawn parallel to one side of a triangle and it cuts the other two sides, then it divides those two sides in the same ratio.

In triangle ABC, if DE is parallel to BC (D on AB, E on AC), then AD/DB = AE/EC.
CriterionWhat you need to prove similarity
AA (or AAA)Two angles of one triangle equal two angles of the other
SSSAll three pairs of corresponding sides in the same ratio
SASOne pair of angles equal AND the two sides around that angle in the same ratio

๐Ÿ“ Finding a length using BPT

In triangle ABC, DE is parallel to BC. D lies on AB with AD = 3 cm and DB = 5 cm. E lies on AC with AE = 4.5 cm. Find EC.

By the Basic Proportionality Theorem: AD/DB = AE/EC.

Substitute the values: 3/5 = 4.5/EC.

Cross-multiply: 3 x EC = 5 x 4.5 = 22.5.

So EC = 22.5 / 3 = 7.5 cm.

โš ๏ธ Note for the 2020+ syllabus: the Pythagoras theorem and the area-ratio theorem are no longer part of the Class 10 'Triangles' proof list in NCERT. Focus your exam prep on similarity criteria and the Basic Proportionality Theorem.

Quick revision

  • โœ“Similar = same shape, sides in equal ratio, angles equal. Congruent = similar AND same size.
  • โœ“Write similarity in matching vertex order, e.g. ABC ~ PQR.
  • โœ“Basic Proportionality Theorem: a line parallel to one side divides the other two sides proportionally.
  • โœ“Three similarity criteria: AA, SSS, SAS.
  • โœ“The ratio of corresponding sides of similar triangles is called the scale factor.

โšก Quick check

In triangle ABC, DE is parallel to BC. If AD = 2 cm, DB = 3 cm and AE = 4 cm, what is EC?

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