JEE (Main + Adv) · Physics

Rotational Motion

15 practice questions with full step-by-step solutions — free, no sign-up.

This chapter has

5
easy
7
medium
3
hard

Rotational Motion — solved practice questions

8 JEE Physics questions with step-by-step solutions. Attempt each, then reveal the answer.

  1. Q1easy

    The moment of inertia of a uniform solid sphere of mass M and radius R about a diameter is:

    • A(1/2)MR^2
    • B(2/5)MR^2
    • CMR^2
    • D(2/3)MR^2
    Show answer & solution

    Correct answer: (B) (2/5)MR^2

    The standard result for a solid sphere about a diameter is I = (2/5)MR^2.

  2. Q2medium

    A solid sphere rolls without slipping down an incline of angle 30 degrees (g = 10 m/s^2). Its linear acceleration is:

    • A5 m/s^2
    • B2.5 m/s^2
    • C25/7 m/s^2
    • D10 m/s^2
    Show answer & solution

    Correct answer: (C) 25/7 m/s^2

    For rolling without slipping, a = g sin(theta)/(1 + I/MR^2) = 10*0.5/(1 + 2/5) = 5/1.4 = 25/7 = 3.57 m/s^2.

  3. Q3medium

    A solid sphere rolls without slipping. The fraction of its total kinetic energy that is rotational is:

    • A2/7
    • B5/7
    • C1/2
    • D1/3
    Show answer & solution

    Correct answer: (A) 2/7

    Rotational KE = (1/2)(2/5 MR^2)(v/R)^2 = (1/5)Mv^2 and total = (7/10)Mv^2, so the fraction is (1/5)/(7/10) = 2/7.

  4. Q4easy

    A ballet dancer spins with her arms outstretched. When she pulls her arms in, reducing her moment of inertia to half, her angular velocity:

    • Ahalves
    • Bstays the same
    • Cbecomes one-fourth
    • Ddoubles
    Show answer & solution

    Correct answer: (D) doubles

    With no external torque, angular momentum L = I*omega is conserved. Halving I doubles omega.

  5. Q5easy

    A uniform disc of mass 2 kg and radius 0.5 m rotates about its central axis. Its moment of inertia is:

    • A0.5 kg m^2
    • B0.25 kg m^2
    • C1 kg m^2
    • D0.125 kg m^2
    Show answer & solution

    Correct answer: (B) 0.25 kg m^2

    For a disc about its central axis, I = (1/2)MR^2 = (1/2)(2)(0.5)^2 = 0.25 kg m^2.

  6. Q6medium

    A flywheel starts from rest and gains angular speed under a constant angular acceleration of 2 rad/s^2. The angle turned through in the first 5 s is:

    • A10 rad
    • B50 rad
    • C25 rad
    • D5 rad
    Show answer & solution

    Correct answer: (C) 25 rad

    theta = omega0*t + (1/2)*alpha*t^2 = 0 + (1/2)(2)(25) = 25 rad.

  7. Q7easy

    Two point masses of 2 kg and 3 kg are placed at x = 0 and x = 5 m on a light rod. The centre of mass lies at:

    • A2.5 m
    • B2 m
    • C3.5 m
    • D3 m
    Show answer & solution

    Correct answer: (D) 3 m

    x_cm = (m1x1 + m2x2)/(m1 + m2) = (2*0 + 3*5)/(2+3) = 15/5 = 3 m.

  8. Q8medium

    A ring, a disc, and a solid sphere of the same mass and radius are released from rest at the top of the same incline and roll down without slipping. Which reaches the bottom first?

    • ASolid sphere
    • BDisc
    • CRing
    • DAll together
    Show answer & solution

    Correct answer: (A) Solid sphere

    Acceleration a = g sin(theta)/(1 + I/MR^2) is largest for the smallest I/MR^2. The solid sphere has 2/5, the smallest, so it arrives first.

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