Time, Speed, Distance & Time-and-Work: The Rate Formula That Cracks Both

One idea -- Rate x Time = Total -- powers trains, average speed, relative speed, and pipes & cisterns. Learn the 5/18 shortcut, the average-speed trap, and the add-the-rates method to lock in easy RRB NTPC Maths marks.

By the PadhoDost Team ยท ๐Ÿ“– 7 min read ยท Updated 4 August 2026

Part of Railway Exams (RRB) prep

๐Ÿง  The auto-rickshaw meter

Picture an auto meter ticking as you ride. How far you go depends on just two things: how fast the auto moves (speed) and how long you sit in it (time). Speed x Time = Distance. That one sentence is the whole chapter. Time-Speed-Distance (TSD) and Time-and-Work look like two separate topics, but both are really the same idea: RATE x TIME = TOTAL. Master the rate idea once, and trains, boats, pipes and painters all fall in line. Padho, dost -- this is one of the highest-scoring, most predictable areas in RRB NTPC Maths.

In NTPC CBT-1 you face 100 questions in 90 minutes: 40 General Awareness, 30 Maths, 30 Reasoning, with +1 for a correct answer and -1/3 for a wrong one. That is roughly 54 seconds per question. TSD and Time-and-Work together hand you 4 to 6 near-guaranteed Maths marks IF you know the formulas cold and stay calm. Let us build that speed.

Part 1: The core Speed-Time-Distance triangle

Distance = Speed x Time | Speed = Distance / Time | Time = Distance / Speed
๐Ÿ’ก The unit-conversion shortcut you MUST memorise: to change km/h into m/s, multiply by 5/18. To change m/s into km/h, multiply by 18/5. Example: 54 km/h x 5/18 = 15 m/s. Almost every train question hides right here.
Average speed for equal distances (go at x, return at y) = 2xy / (x + y). This is NOT the simple average (x + y)/2 -- that is the classic trap.

๐Ÿ“ Worked example: average speed

Question: A man goes to a town at 60 km/h and returns along the same road at 40 km/h. Find his average speed for the whole trip.

Trap answer: (60 + 40)/2 = 50 km/h. WRONG, because he spends more time on the slower leg.

Correct formula (equal distance both ways): 2xy / (x + y).

= (2 x 60 x 40) / (60 + 40)

= 4800 / 100

= 48 km/h. That is the answer.

Part 2: Relative speed, trains and platforms

When two objects move, we combine their speeds. Same direction: SUBTRACT the speeds (they pull apart slowly). Opposite directions: ADD the speeds (they close in fast). A train question is just a distance-covered question where the distance includes the length of the train itself.

SituationDistance coveredSpeed to use
Train crosses a pole / standing manLength of trainTrain's own speed
Train crosses a platform / bridgeTrain length + platform lengthTrain's own speed
Two trains, opposite directionsSum of both lengthsSum of speeds
Two trains, same directionSum of both lengthsDifference of speeds

๐Ÿ“ Worked example: train crossing a platform

Question: A 240 m long train runs at 54 km/h. How long does it take to cross a 360 m platform?

Step 1 -- Convert speed: 54 x 5/18 = 15 m/s.

Step 2 -- Total distance = train + platform = 240 + 360 = 600 m.

Step 3 -- Time = Distance / Speed = 600 / 15.

Answer = 40 seconds.

Part 3: Time and Work (and Pipes & Cisterns)

Same rate idea, new costume. If A finishes a job in 10 days, then in ONE day A does 1/10 of the work. That 1/10 is A's rate. To combine workers, simply ADD their one-day rates. Pipes and cisterns work the same way: a filling pipe has a positive rate, and a draining or leaking pipe has a NEGATIVE rate, so you subtract it.

If A alone takes 'a' days and B alone takes 'b' days, together they take (a x b) / (a + b) days. (Add the daily rates 1/a + 1/b, then flip.)

Method: A and B working together

  1. 1A does the job in 10 days, so A's 1-day work = 1/10.
  2. 2B does the job in 15 days, so B's 1-day work = 1/15.
  3. 3Add the rates: 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6.
  4. 4Together they do 1/6 of the work per day.
  5. 5Flip it: total time = 6 days. Done.
โš ๏ธ Common mistake: students ADD the days (10 + 15 = 25) or average them. Never add or average days -- add the RATES (1/days). Two people working together must be FASTER than either one alone, so the combined time is always LESS than the smaller number (here, less than 10).

60-second revision card

  • โœ“km/h to m/s: multiply by 5/18. m/s to km/h: multiply by 18/5.
  • โœ“Average speed (equal distance): 2xy/(x+y), never (x+y)/2.
  • โœ“Same direction: subtract speeds. Opposite direction: add speeds.
  • โœ“Train + platform = add both lengths for the distance.
  • โœ“Time & Work: add one-day rates (1/a + 1/b), then flip for the combined time.
  • โœ“Pipes: filling is +rate, leaking/emptying is -rate. The net rate decides the time.

โšก Quick check

A can finish a piece of work in 12 days and B can finish the same work in 6 days. Working together, how many days will they take?

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