SSC CGL & Banking · Quantitative Aptitude

Compound Interest

15 practice questions with full step-by-step solutions, plus a concept-first explainer — free, no sign-up.

What you'll learn

Learn Compound Interest through a simple snowball analogy, master the amount formula for annual, half-yearly and quarterly compounding, see a worked example, use the CI-minus-SI shortcuts, and test yourself with a quiz for SSC-CGL.

Read Compound Interest — Interest That Grows on Itself

This chapter has

3
easy
6
medium
6
hard

Compound Interest — solved practice questions

8 SSC / Banking Quantitative Aptitude questions with step-by-step solutions. Attempt each, then reveal the answer.

  1. Q1easy

    The formula for Compound Interest Amount is:

    • AP(1+R/100)ⁿ
    • BP×R×T/100
    • CP+PRT/100
    • DP(1−R/100)ⁿ
    Show answer & solution

    Correct answer: (A) P(1+R/100)ⁿ

    A = P(1 + R/100)ⁿ, where P=principal, R=rate%, n=years.

  2. Q2easy

    Compound interest on ₹1000 at 10% p.a. for 2 years is:

    • A₹200
    • B₹205
    • C₹210
    • D₹220
    Show answer & solution

    Correct answer: (C) ₹210

    A = 1000×(1.1)² = 1210. CI = 1210−1000 = ₹210.

  3. Q3easy

    Simple interest on ₹1000 at 10% for 2 years is ₹200. CI for the same is ₹210. The difference is:

    • A₹5
    • B₹10
    • C₹15
    • D₹20
    Show answer & solution

    Correct answer: (B) ₹10

    CI − SI = ₹10. The extra ₹10 is interest on the first year's interest.

  4. Q4medium

    ₹2000 is invested at 5% p.a. CI for 3 years. Amount after 3 years:

    • A₹2300
    • B₹2310
    • C₹2315.25
    • D₹2320
    Show answer & solution

    Correct answer: (C) ₹2315.25

    A = 2000×(1.05)³ = 2000×1.157625 = ₹2315.25.

  5. Q5medium

    At what rate % p.a. does ₹1000 become ₹1210 in 2 years (CI)?

    • A5%
    • B10%
    • C15%
    • D20%
    Show answer & solution

    Correct answer: (B) 10%

    1210 = 1000(1+R/100)² → (1+R/100)² = 1.21 → 1+R/100 = 1.1 → R = 10%.

  6. Q6hard

    The difference between CI and SI on ₹P at R% for 2 years is:

    • AP(R/100)
    • BP(R/100)²
    • CPR²/100
    • DPR/10000
    Show answer & solution

    Correct answer: (B) P(R/100)²

    CI − SI = P(R/100)². Derived from: CI = P[(1+R/100)²−1], SI = 2PR/100.

  7. Q7hard

    A sum doubles at 8% CI in approximately how many years?

    • A7 years
    • B8 years
    • C9 years
    • D10 years
    Show answer & solution

    Correct answer: (C) 9 years

    Rule of 72: years ≈ 72/8 = 9 years.

  8. Q8hard

    ₹5000 at 4% p.a. CI, compounded half-yearly for 1 year. Amount:

    • A₹5200
    • B₹5202
    • C₹5204
    • D₹5210
    Show answer & solution

    Correct answer: (B) ₹5202

    Half-yearly rate = 2%, periods = 2. A = 5000×(1.02)² = 5000×1.0404 = ₹5202.

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