Class 12 (CBSE) · Chemistry
Electrochemistry
15 practice questions with full step-by-step solutions, plus a concept-first explainer — free, no sign-up.
What you'll learn
A friendly, NCERT-aligned walkthrough of Class 12 Electrochemistry: how galvanic cells turn reactions into electricity, standard electrode potentials and the SHE, calculating cell EMF, the Nernst equation with a worked numerical, conductance of solutions, and electrolysis with Faraday's laws.
Read Electrochemistry Made Simple: Cells, EMF, Nernst and ElectrolysisThis chapter has
Electrochemistry — solved practice questions
8 Class 12 Chemistry questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1easy
In a galvanic (voltaic) cell, oxidation takes place at the:
- ACathode, which is the positive electrode
- BAnode, which is the negative electrode
- CCathode, which is the negative electrode
- DSalt bridge
Show answer & solution
Correct answer: (B) Anode, which is the negative electrode
In a galvanic cell, oxidation occurs at the anode, which is the negative electrode, while reduction occurs at the positive cathode.
- Q2easy
The standard hydrogen electrode (SHE) is assigned a standard electrode potential of:
- A+1.00 V
- B-1.00 V
- C0.00 V
- D+0.76 V
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Correct answer: (C) 0.00 V
By convention, the standard hydrogen electrode is the reference electrode and is assigned a standard potential of exactly 0.00 V at all temperatures.
- Q3medium
The SI unit of molar conductivity when concentration is expressed in mol m^-3 is:
- AS cm^2 mol^-1
- BS m^-1
- Cohm cm
- DS m^2 mol^-1
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Correct answer: (D) S m^2 mol^-1
Molar conductivity = conductivity / concentration. With conductivity in S m^-1 and concentration in mol m^-3, the SI unit is S m^2 mol^-1.
- Q4medium
For the cell reaction to be spontaneous under standard conditions, the standard cell potential (E0 cell) and standard Gibbs energy (Delta G0) must satisfy:
- AE0 cell > 0 and Delta G0 > 0
- BE0 cell > 0 and Delta G0 < 0
- CE0 cell < 0 and Delta G0 < 0
- DE0 cell = 0 and Delta G0 > 0
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Correct answer: (B) E0 cell > 0 and Delta G0 < 0
Delta G0 = -nFE0 cell. A spontaneous reaction requires Delta G0 < 0, which means E0 cell must be positive.
- Q5medium
According to the Nernst equation at 298 K, the potential of an electrode M(n+) + n e- -> M is given by E = E0 - (0.0591/n) log(1/[M^n+]). If [M^n+] increases, the electrode potential:
- ADecreases
- BIncreases
- CRemains unchanged
- DBecomes zero
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Correct answer: (B) Increases
As [M^n+] increases, log(1/[M^n+]) becomes more negative, so the subtracted term decreases, making E larger. A higher ion concentration favours reduction, raising the electrode potential.
- Q6medium
How many faradays of charge are required to deposit 1 mole of aluminium from molten Al2O3 (Al^3+ + 3e- -> Al)?
- A1 F
- B2 F
- C3 F
- D0.5 F
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Correct answer: (C) 3 F
Each Al^3+ ion needs 3 electrons, so depositing 1 mole of Al requires 3 moles of electrons, i.e. 3 faradays of charge.
- Q7hard
The conductivity of an electrolytic solution generally _____ with dilution, while the molar conductivity _____ with dilution.
- Adecreases; increases
- Bincreases; decreases
- Cincreases; increases
- Ddecreases; decreases
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Correct answer: (A) decreases; increases
On dilution, the number of ions per unit volume falls, so conductivity decreases. Molar conductivity increases because it accounts for all ions from a fixed amount of electrolyte, which become more mobile/dissociated.
- Q8medium
Kohlrausch's law of independent migration of ions is especially useful for calculating the limiting molar conductivity of:
- AStrong electrolytes only
- BNon-electrolytes
- CMolten salts
- DWeak electrolytes, which cannot be obtained by extrapolation
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Correct answer: (D) Weak electrolytes, which cannot be obtained by extrapolation
For weak electrolytes, molar conductivity does not reach a limiting value by simple extrapolation. Kohlrausch's law lets us calculate it by adding the limiting ionic conductivities of the constituent ions.
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