Class 12 (CBSE) · Board Sample Papers (CBSE)
Class 12 Mathematics — CBSE Board Sample Paper
19 practice questions with full step-by-step solutions — free, no sign-up.
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Class 12 Mathematics — CBSE Board Sample Paper — solved practice questions
8 Class 12 Board Sample Papers (CBSE) questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1medium
If for a square matrix A of order 3, A·(adj A) = [[2025, 0, 0], [0, 2025, 0], [0, 0, 2025]], then the value of |A| + |adj A| is equal to:
- A1
- B2025 + 1
- C2025² + 45
- D2025 + 2025²
Show answer & solution
Correct answer: (D) 2025 + 2025²
Since A·(adj A) = |A|·I₃ = 2025 I₃, we get |A| = 2025. Also |adj A| = |A|^(3−1) = 2025². Hence |A| + |adj A| = 2025 + 2025².
- Q2medium
Assume X, Y, Z, W and P are matrices of order 2×n, 3×k, 2×p, n×3 and p×k, respectively. Then the restriction on n, k and p so that PY + WY will be defined are:
- Ak = 3, p = n
- Bk is arbitrary, p = 2
- Cp is arbitrary, k = 3
- Dk = 2, p = 3
Show answer & solution
Correct answer: (A) k = 3, p = n
For PY (p×k times 3×k) to be defined, k = 3, giving order p×3; WY (n×3 times 3×k) has order n×k. For the sum PY + WY the orders must match, so p = n. Hence k = 3 and p = n.
- Q3easy
The interval in which the function f defined by f(x) = eˣ is strictly increasing, is
- A[1, ∞)
- B(−∞, 0)
- C(−∞, ∞)
- D(0, ∞)
Show answer & solution
Correct answer: (C) (−∞, ∞)
f'(x) = eˣ > 0 for every real x, so f is strictly increasing on the whole real line (−∞, ∞).
- Q4easy
If A and B are non-singular matrices of the same order with |A| = 5, then the value of |B⁻¹AB|² is equal to
- A5
- B5²
- C5⁴
- D5⁵
Show answer & solution
Correct answer: (B) 5²
|B⁻¹AB| = |B⁻¹||A||B| = |A| = 5, so |B⁻¹AB|² = 5².
- Q5medium
The value of 'n', such that the differential equation xⁿ (dy/dx) = y(logₑ y − logₑ x + 1); (x, y ∈ ℝ⁺) is homogeneous, is
- A0
- B1
- C2
- D3
Show answer & solution
Correct answer: (B) 1
Writing dy/dx = (y/xⁿ)(logₑ(y/x) + 1), the right-hand side is a homogeneous function of degree 0 only when n = 1.
- Q6medium
If the points (x₁, y₁), (x₂, y₂) and (x₁ + x₂, y₁ + y₂) are collinear, then x₁y₂ is equal to
- Ax₂y₁
- Bx₁y₁
- Cx₂y₂
- Dx₁x₂
Show answer & solution
Correct answer: (A) x₂y₁
The collinearity determinant condition reduces to x₁y₂ − x₂y₁ = 0, hence x₁y₂ = x₂y₁.
- Q7medium
If A = [[0, 1, c], [−1, a, b], [−2, 3, 0]] is a skew-symmetric matrix, then the value of a − b − c is
- A1
- B2
- C3
- D4
Show answer & solution
Correct answer: (A) 1
In a skew-symmetric matrix the diagonal entries are zero (a = 0) and aᵢⱼ = −aⱼᵢ, giving c = 2 and b = −3. Hence a − b − c = 0 − (−3) − 2 = 1.
- Q8medium
For any two events A and B, if P(Ā) = 1/2, P(B̄) = 2/3 and P(A ∩ B) = 1/4, then P(Ā/B̄) equals:
- A3/8
- B8/9
- C5/8
- D1/4
Show answer & solution
Correct answer: (C) 5/8
Here P(A) = 1/2 and P(B) = 1/3, so P(A∪B) = 1/2 + 1/3 − 1/4 = 7/12. Then P(Ā/B̄) = P((A∪B)')/P(B') = (1 − 7/12)/(2/3) = (5/12)/(2/3) = 5/8.
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