Class 11 (CBSE) · Chemistry
Some Basic Concepts of Chemistry
15 practice questions with full step-by-step solutions, plus a concept-first explainer — free, no sign-up.
What you'll learn
A patient, from-scratch guide to the mole, Avogadro's number, molar mass, empirical vs molecular formulas and stoichiometry — with fully worked numericals aligned to the NCERT Class 11 syllabus.
Read The Mole Concept, Made Simple — Some Basic Concepts of ChemistryThis chapter has
Some Basic Concepts of Chemistry — solved practice questions
8 Class 11 Chemistry questions with step-by-step solutions. Attempt each, then reveal the answer.
- Q1easy
How many significant figures are there in the measurement 0.00520?
- A2
- B3
- C4
- D5
Show answer & solution
Correct answer: (B) 3
Leading zeros are not significant, but the trailing zero after the decimal point is. So 5, 2 and 0 are significant, giving 3 significant figures.
- Q2easy
The SI base unit for the amount of substance is the:
- Akilogram
- Bkelvin
- Cmole
- Dcandela
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Correct answer: (C) mole
Amount of substance is measured in the mole (mol), which is one of the seven SI base units.
- Q3easy
The molar mass of carbon dioxide (CO2) is (C = 12, O = 16):
- A44 g/mol
- B28 g/mol
- C32 g/mol
- D46 g/mol
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Correct answer: (A) 44 g/mol
Molar mass of CO2 = 12 + 2 x 16 = 12 + 32 = 44 g/mol.
- Q4medium
How many moles are present in 11 g of CO2? (Molar mass of CO2 = 44 g/mol)
- A1 mol
- B0.75 mol
- C0.5 mol
- D0.25 mol
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Correct answer: (D) 0.25 mol
Number of moles = given mass / molar mass = 11 / 44 = 0.25 mol.
- Q5easy
The number of particles present in one mole of a substance (Avogadro's number) is approximately:
- A6.022 x 10^22
- B3.011 x 10^23
- C6.022 x 10^23
- D1.2 x 10^24
Show answer & solution
Correct answer: (C) 6.022 x 10^23
One mole contains Avogadro's number of particles, which is 6.022 x 10^23.
- Q6easy
The statement that mass can neither be created nor destroyed in a chemical reaction is known as the:
- ALaw of definite proportions
- BLaw of conservation of mass
- CLaw of multiple proportions
- DGay-Lussac's law of gaseous volumes
Show answer & solution
Correct answer: (B) Law of conservation of mass
This is the Law of Conservation of Mass, proposed by Antoine Lavoisier, stating total mass of reactants equals total mass of products.
- Q7medium
The empirical formula of glucose (molecular formula C6H12O6) is:
- ACH2O
- BC6H12O6
- CCHO
- DC2H4O2
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Correct answer: (A) CH2O
Dividing the subscripts by their highest common factor 6 gives the simplest whole-number ratio C:H:O = 1:2:1, so the empirical formula is CH2O.
- Q8medium
The mass percent of nitrogen in ammonia (NH3) is (N = 14, H = 1):
- A17.65%
- B46.67%
- C25%
- D82.35%
Show answer & solution
Correct answer: (D) 82.35%
Mass % of N = (mass of N / molar mass of NH3) x 100 = (14 / 17) x 100 = 82.35%.
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